Use Descartes' Rule of Signs to Determine the Possible Number $$f ( x ) = 7 x ^ { 8 } + 3 x ^ { 6 } + 2 x ^ { 4 } + 5 x ^ { 2 } + 2$$

Multiple Choice

Use Descartes' Rule of Signs to determine the possible number of positive real zeros and the possible number of negative
real zeros for the function.
- $$f ( x ) = 7 x ^ { 8 } + 3 x ^ { 6 } + 2 x ^ { 4 } + 5 x ^ { 2 } + 2$$

A)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 4 & 4 & 0\end{array}$

B)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 4 & 0 & 4\end{array}$

C)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 0 & 4 & 4\end{array}$

D)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 0 & 0 & 8\end{array}$