Use Descartes' Rule of Signs to Determine the Possible Number $$f ( x ) = - 4 x ^ { 4 } + 2 x ^ { 3 } - 3 x ^ { 2 } + 9 x - 6$$

Multiple Choice

Use Descartes' Rule of Signs to determine the possible number of positive real zeros and the possible number of negative
real zeros for the function.
- $$f ( x ) = - 4 x ^ { 4 } + 2 x ^ { 3 } - 3 x ^ { 2 } + 9 x - 6$$

A)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 2 & 2 & 0 \\2 & 0 & 2 \\0 & 4 & 0 \\0 & 2 & 2 \\0 & 0 & 4\end{array}$
B)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 4 & 0 & 0 \\2 & 2 & 0 \\2 & 0 & 2 \\0 & 4 & 0 \\0 & 2 & 2 \\0 & 0 & 4\end{array}$

C)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 2 & 2 & 0 \\2 & 0 & 2 \\0 & 2 & 2 \\0 & 0 & 2\end{array}$

D)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 4 & 0 & 0 \\2 & 0 & 2 \\0 & 0 & 4\end{array}$