Give a Rule for the Piecewise-Defined Function B) f(x)={−x3x−2 if x<1 if x≥1
Question 34
Question 34
Multiple Choice
Give a rule for the piecewise-defined function. Then give the domain and range. -
A) f(x) ={3xx+2 if x<1; Domain: (∞,∞) , Range: (∞,1) ∪[3,∞) if x≥1 B) f(x) ={−x3x−2 if x<1 if x≥1 Domain: (∞,1) ∪[3,∞) , Range: (∞,∞) C) f(x) ={x3x+2 if x<1 if x≥1 Domain: (∞,∞) , Range: (∞,1) ∪[3,∞) D) f(x) ={x3x−2 if x<1 if x≥1 ; Domain: (∞,1) ∪[3,∞) , Range: (∞,∞)
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![Give a rule for the piecewise-defined function. Then give the domain and range. - A) f ( x ) = \left\{ \begin{array} { l l } \sqrt [ 3 ] { x } & \text { if } x < 1 ; \text { Domain: } ( \infty , \infty ) , \text { Range: } ( \infty , 1 ) \cup [ 3 , \infty ) \\ x + 2 & \text { if } x \geq 1 \end{array} \right. B) f ( x ) = \left\{ \begin{array} { l l } - x ^ { 3 } & \text { if } x < 1 \\ x - 2 & \text { if } x \geq 1 \end{array} \right. Domain: ( \infty , 1 ) \cup [ 3 , \infty ) , Range: ( \infty , \infty ) C) f ( x ) = \left\{ \begin{array} { l l } x ^ { 3 } & \text { if } x < 1 \\ x + 2 & \text { if } x \geq 1 \end{array} \right. Domain: ( \infty , \infty ) , Range: ( \infty , 1 ) \cup [ 3 , \infty ) D) f ( x ) = \left\{ \begin{array} { l l } x ^ { 3 } & \text { if } x < 1 \\ x - 2 & \text { if } x \geq 1 \end{array} \right. ; Domain: ( \infty , 1 ) \cup [ 3 , \infty ) , Range: ( \infty , \infty )](https://d2lvgg3v3hfg70.cloudfront.net/TB7514/11ed7971_9237_d0d5_9733_17fdaea58394_TB7514_11.jpg)
