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Write an Equation for the Hyperbola 60ft60 \mathrm { ft }

Question 157

Multiple Choice

Write an equation for the hyperbola.
-A nuclear cooling tower cross section is a hyperbola having a diameter of 60ft60 \mathrm { ft } at the center. The distance between the two foci is 92ft92 \mathrm { ft } . What is the equation for the hyperbola?


A) x2900y21216=5\frac { x ^ { 2 } } { 900 } - \frac { y ^ { 2 } } { 1216 } = 5

B) x2900y21218=1\frac { x ^ { 2 } } { 900 } - \frac { y ^ { 2 } } { 1218 } = 1

C) x2900y22116=1\frac { x ^ { 2 } } { 900 } - \frac { y ^ { 2 } } { 2116 } = 1

D) x2900y21216=1\frac { x ^ { 2 } } { 900 } - \frac { y ^ { 2 } } { 1216 } = 1

Correct Answer:

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