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Decide What Values of the Variable Cannot Possibly Be Solutions 1x31x+7=12\frac { 1 } { x - 3 } - \frac { 1 } { x + 7 } = 12

Question 3

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 1x31x+7=12\frac { 1 } { x - 3 } - \frac { 1 } { x + 7 } = 12


A) 7,3- 7,3
B) 17,13- \frac { 1 } { 7 } , \frac { 1 } { 3 }
C) 3,7- 3,7
D) 13,17- \frac { 1 } { 3 } , \frac { 1 } { 7 }

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