Decide What Values of the Variable Cannot Possibly Be Solutions $$\frac { 16 } { x + 2 } = 1 + \frac { 2 } { x - 4 }$$

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $$\frac { 16 } { x + 2 } = 1 + \frac { 2 } { x - 4 }$$

A) $\{ - 12 \}$
B) $\varnothing$
C) $\{ 6,10 \}$
D) $\{ - 2,4 \}$