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Decide What Values of the Variable Cannot Possibly Be Solutions 5x26x4=15xx4+6\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6

Question 112

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 5x26x4=15xx4+6\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6


A) {65,3}\left\{ - \frac { 6 } { 5 } , 3 \right\}

B) {65,3}\left\{ \frac { 6 } { 5 } , - 3 \right\}

C) {3}\{ 3 \}

D) {5±1053}\left\{ \frac { - 5 \pm \sqrt { 105 } } { 3 } \right\}

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