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Decide What Values of the Variable Cannot Possibly Be Solutions xx88x+8=128x264\frac { x } { x - 8 } - \frac { 8 } { x + 8 } = \frac { 128 } { x ^ { 2 } - 64 }

Question 30

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- xx88x+8=128x264\frac { x } { x - 8 } - \frac { 8 } { x + 8 } = \frac { 128 } { x ^ { 2 } - 64 }


A) \varnothing

B) {18}\left\{ \frac { 1 } { 8 } \right\}

C) {±8}\{ \pm 8 \}

D) {±8i}\{ \pm 8 i \}

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