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Decide What Values of the Variable Cannot Possibly Be Solutions (x+3)2/32(x+3)1/33=0( x + 3 ) ^ { 2 / 3 } - 2 ( x + 3 ) ^ { 1 / 3 } - 3 = 0

Question 44

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- (x+3) 2/32(x+3) 1/33=0( x + 3 ) ^ { 2 / 3 } - 2 ( x + 3 ) ^ { 1 / 3 } - 3 = 0


A) \varnothing
B) {24,4}\{ - 24 , - 4 \}
C) {24,4}\{ 24 , - 4 \}
D) {5,1}\{ 5,1 \}

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