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Factor by Any Method 20z6+3z3920 z ^ { 6 } + 3 z ^ { 3 } - 9

Question 549

Multiple Choice

Factor by any method.
- 20z6+3z3920 z ^ { 6 } + 3 z ^ { 3 } - 9


A) (4z3+3) (5z33) \left( 4 z ^ { 3 } + 3 \right) \left( 5 z ^ { 3 } - 3 \right)
B) (5z3+3) (4z33) \left( 5 z ^ { 3 } + 3 \right) \left( 4 z ^ { 3 } - 3 \right)
C) (4z3+1) (5z39) \left( 4 z ^ { 3 } + 1 \right) \left( 5 z ^ { 3 } - 9 \right)
D) 20(z33) (z3+3) 20 \left( z ^ { 3 } - 3 \right) \left( z ^ { 3 } + 3 \right)

Correct Answer:

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