Solve the Problem $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$

Multiple Choice

Solve the problem.
-The length of the diagonal of a rectangle is given by $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$ where $L$ and $W$ are the length and width of the rectangle. What is the length of the diagonal, D, of a rectangle that is 68 inches long and 41 inches wide? Round your answer to the nearest tenth of an inch, if necessary.

A) $52.8 \mathrm { in }$ .
B) $54.2 \mathrm { in }$ .
C) $10.4 \mathrm { in }$ .
D) $79.4 \mathrm { in }$ .