Solve the Problem $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$

Multiple Choice

Solve the problem.
-The length of the diagonal of a box is given by $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$ where $L , W$ , and $H$ are the length, width, and height of the box. Find the length of the diagonal, D, of a box that is $4 \mathrm { ft }$ long, $2 \mathrm { ft }$ high, and $4 \mathrm { ft }$ wide. Give the exact value.

A) $6 \mathrm { ft }$
B) $4 \sqrt { 2 } \mathrm { ft }$
C) $10 \mathrm { ft }$
D) $32 \mathrm { ft }$