Inc. Technology reported the results of consumer survey in which 300 Internet users indicated their level of agreement with the following statement: "The government needs to be able to scan Internet messages and user communications to prevent fraud and other crimes." The possible responses were "agree strongly", "agree somewhat", "disagree somewhat", and "disagree strongly". The number of Internet users in each category is summarized in the table.

\begin{array}{l|l}\text { RESPONSE } & \text { NUMBER } \\\hline \text { Agree Strongly } & 60 \\\text { Agree Somewhat } & 110 \\\text { Disagree Somewhat } & 80 \\\text { Disagree Strongly } & 50\end{array}

In order to determine whether the true proportions of Internet users in each response category differ, a one-way chi-square analysis should be conducted. When calculating the test statistic, what values for the expected counts should be used in the calculation?
A)

\mathrm { E } _ { 1 } = 75 , \mathrm { E } _ { 2 } = 75 , \mathrm { E } _ { 3 } = 75 , \mathrm { E } _ { 4 } = 75

\mathrm { E } _ { 1 } = 300 , \mathrm { E } _ { 2 } = 300 , \mathrm { E } _ { 3 } = 300 , \mathrm { E } _ { 4 } = 300

\mathrm { E } _ { 1 } = 0.25 , \mathrm { E } _ { 2 } = 0.25 , \mathrm { E } _ { 3 } = 0.25 , \mathrm { E } _ { 4 } = 0.25

\mathrm { E } _ { 1 } = 60 , \mathrm { E } _ { 2 } = 110 , \mathrm { E } _ { 3 } = 80 , \mathrm { E } _ { 4 } = 50

A New Coffeehouse Wishes to See Whether Customers Have Any α=0.01\alpha = 0.01α=0.01

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A New Coffeehouse Wishes to See Whether Customers Have Any $\alpha = 0.01$

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