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Find the Inverse Function F-1 of the Function F f(x)=3sinx2f ( x ) = 3 \sin x - 2

Question 164

Multiple Choice

Find the inverse function f-1 of the function f.
- f(x) =3sinx2f ( x ) = 3 \sin x - 2


A) f1(x) =3sin1x2f ^ { - 1 } ( x ) = 3 \sin ^ { - 1 } x - 2
B) f1(x) =sin1(x+23) f ^ { - 1 } ( x ) = \sin ^ { - 1 } \left( \frac { x + 2 } { 3 } \right)
C) f1(x) =cos(x+23) \mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \cos \left( \frac { \mathrm { x } + 2 } { 3 } \right)
D) f1(x) =sin1(x+32) f ^ { - 1 } ( x ) = \sin ^ { - 1 } \left( \frac { x + 3 } { 2 } \right)

Correct Answer:

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