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Solve the Problem R=vO2sin2θg where g=32.2\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2

Question 23

Multiple Choice

Solve the problem.
-The path of a projectile fired at an inclination θ to the horizontal with an initial speed vo is a parabola. The range R of the projectile, the horizontal distance that the projectile travels, is found by the formula
Feet per second per second or g = 9.8 meters per second per second. Find the R=vO2sin2θg where g=32.2\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2 range of a projectile fired with an initial velocity of 174 feet per second at an angle of 35° to the horizontal.
Round your answer to two decimal places.


A) 883.54 ft
B) 883.44 ft
C) 1,078.61 ft
D) 539.30 ft

Correct Answer:

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