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Solve the Problem h(x)=32x2(300)2+x+300h ( x ) = \frac { - 32 x ^ { 2 } } { ( 300 ) ^ { 2 } } + x + 300

Question 199

Multiple Choice

Solve the problem.
-A projectile is fired from a cliff 300 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 300 feet per second. The height h of the projectile above the water is given by h(x) =32x2(300) 2+x+300h ( x ) = \frac { - 32 x ^ { 2 } } { ( 300 ) ^ { 2 } } + x + 300 where x is the horizontal distance of the projectile from the base of the cliff. How far from the base of the cliff is
The height of the projectile a maximum?


A) 1,003.13 ft
B) 1,406.25 ft
C) 703.13 ft
D) 2,409.38 ft

Correct Answer:

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