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Find the Center (H, K) and Radius R of the Circle

Question 106

Multiple Choice

Find the center (h, k) and radius r of the circle with the given equation.
- 4x2+4y212x+16y5=04 x ^ { 2 } + 4 y ^ { 2 } - 12 x + 16 y - 5 = 0


A) (h,k) =(32,2) ;r=302( \mathrm { h } , \mathrm { k } ) = \left( \frac { 3 } { 2 } , - 2 \right) ; \mathrm { r } = \frac { \sqrt { 30 } } { 2 }
B) (h,k) =(32,2) ;r=352( \mathrm { h } , \mathrm { k } ) = \left( - \frac { 3 } { 2 } , 2 \right) ; \mathrm { r } = \frac { 3 \sqrt { 5 } } { 2 }
C) (h,k) =(32,2) ;r=302( h , k ) = \left( - \frac { 3 } { 2 } , 2 \right) ; r = \frac { \sqrt { 30 } } { 2 }
D) (h,k) =(32,2) ;r=352( h , k ) = \left( \frac { 3 } { 2 } , - 2 \right) ; r = \frac { 3 \sqrt { 5 } } { 2 }

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