Solved

Find the Standard Form of the Equation of the Hyperbola (y1)29(x1)216=1\frac { ( y - 1 ) ^ { 2 } } { 9 } - \frac { ( x - 1 ) ^ { 2 } } { 16 } = 1

Question 176

Multiple Choice

Find the standard form of the equation of the hyperbola.
- Find the standard form of the equation of the hyperbola. -  A)   \frac { ( y - 1 )  ^ { 2 } } { 9 } - \frac { ( x - 1 )  ^ { 2 } } { 16 } = 1  B)   \frac { ( y - 1 )  ^ { 2 } } { 16 } - \frac { ( x - 1 )  ^ { 2 } } { 9 } = 1  C)   \frac { ( x - 1 )  ^ { 2 } } { 16 } - \frac { ( y - 1 )  ^ { 2 } } { 9 } = 1  D)   \frac { ( x - 1 )  ^ { 2 } } { 9 } - \frac { ( y - 1 )  ^ { 2 } } { 16 } = 1


A) (y1) 29(x1) 216=1\frac { ( y - 1 ) ^ { 2 } } { 9 } - \frac { ( x - 1 ) ^ { 2 } } { 16 } = 1
B) (y1) 216(x1) 29=1\frac { ( y - 1 ) ^ { 2 } } { 16 } - \frac { ( x - 1 ) ^ { 2 } } { 9 } = 1
C) (x1) 216(y1) 29=1\frac { ( x - 1 ) ^ { 2 } } { 16 } - \frac { ( y - 1 ) ^ { 2 } } { 9 } = 1
D) (x1) 29(y1) 216=1\frac { ( x - 1 ) ^ { 2 } } { 9 } - \frac { ( y - 1 ) ^ { 2 } } { 16 } = 1

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions