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Show That the Equation Is Not an Identity by Finding sin(x+π)=sinx\sin ( x + \pi ) = \sin x

Question 187

Multiple Choice

Show that the equation is not an identity by finding a value of x for which both sides are defined but not equal.
- sin(x+π) =sinx\sin ( x + \pi ) = \sin x


A) π2\frac { \pi } { 2 }
B) 0
C) 2π2 \pi
D) π\pi

Correct Answer:

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