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Verify the Identity sin⁡α−sin⁡βsin⁡α+sin⁡β=tan⁡α−β2cot⁡α+β2\frac { \sin \alpha - \sin \beta } { \sin \alpha + \sin \beta } = \tan \frac { \alpha - \beta } { 2 } \cot \frac { \alpha + \beta } { 2 }

Question 53

Essay

Verify the identity.
- sin⁡α−sin⁡βsin⁡α+sin⁡β=tan⁡α−β2cot⁡α+β2\frac { \sin \alpha - \sin \beta } { \sin \alpha + \sin \beta } = \tan \frac { \alpha - \beta } { 2 } \cot \frac { \alpha + \beta } { 2 }

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