Solved

Show That the Equation Is Not an Identity by Finding [π,π,π2]\left[ - \pi , \pi , \frac { \pi } { 2 } \right]

Question 219

Multiple Choice

Show that the equation is not an identity by finding a value of x for which both sides are defined but not equal.
-Graph in a [π,π,π2]\left[ - \pi , \pi , \frac { \pi } { 2 } \right] by [3,3,1][ - 3,3,1 ] viewing rectangle y=2(sinx1sin2x2+sin3x3sin4x4+sin5x5sin6x6+sin7x7) y = 2 \left( \frac { \sin x } { 1 } - \frac { \sin 2 x } { 2 } + \frac { \sin 3 x } { 3 } - \frac { \sin 4 x } { 4 } + \frac { \sin 5 x } { 5 } - \frac { \sin 6 x } { 6 } + \frac { \sin 7 x } { 7 } \right)


A)
 Show that the equation is not an identity by finding a value of x for which both sides are defined but not equal. -Graph in a  \left[ - \pi , \pi , \frac { \pi } { 2 } \right]  by  [ - 3,3,1 ]  viewing rectangle  y = 2 \left( \frac { \sin x } { 1 } - \frac { \sin 2 x } { 2 } + \frac { \sin 3 x } { 3 } - \frac { \sin 4 x } { 4 } + \frac { \sin 5 x } { 5 } - \frac { \sin 6 x } { 6 } + \frac { \sin 7 x } { 7 } \right)   A)    B)    C)    D)
B)
 Show that the equation is not an identity by finding a value of x for which both sides are defined but not equal. -Graph in a  \left[ - \pi , \pi , \frac { \pi } { 2 } \right]  by  [ - 3,3,1 ]  viewing rectangle  y = 2 \left( \frac { \sin x } { 1 } - \frac { \sin 2 x } { 2 } + \frac { \sin 3 x } { 3 } - \frac { \sin 4 x } { 4 } + \frac { \sin 5 x } { 5 } - \frac { \sin 6 x } { 6 } + \frac { \sin 7 x } { 7 } \right)   A)    B)    C)    D)
C)
 Show that the equation is not an identity by finding a value of x for which both sides are defined but not equal. -Graph in a  \left[ - \pi , \pi , \frac { \pi } { 2 } \right]  by  [ - 3,3,1 ]  viewing rectangle  y = 2 \left( \frac { \sin x } { 1 } - \frac { \sin 2 x } { 2 } + \frac { \sin 3 x } { 3 } - \frac { \sin 4 x } { 4 } + \frac { \sin 5 x } { 5 } - \frac { \sin 6 x } { 6 } + \frac { \sin 7 x } { 7 } \right)   A)    B)    C)    D)
D)
 Show that the equation is not an identity by finding a value of x for which both sides are defined but not equal. -Graph in a  \left[ - \pi , \pi , \frac { \pi } { 2 } \right]  by  [ - 3,3,1 ]  viewing rectangle  y = 2 \left( \frac { \sin x } { 1 } - \frac { \sin 2 x } { 2 } + \frac { \sin 3 x } { 3 } - \frac { \sin 4 x } { 4 } + \frac { \sin 5 x } { 5 } - \frac { \sin 6 x } { 6 } + \frac { \sin 7 x } { 7 } \right)   A)    B)    C)    D)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions