Solved

Solve the Equation on the Interval [0, 2π) cos2x=22\cos 2 x = \frac { \sqrt { 2 } } { 2 }

Question 60

Multiple Choice

Solve the equation on the interval [0, 2π) .
- cos2x=22\cos 2 x = \frac { \sqrt { 2 } } { 2 }


A) π8,7π8,9π8,15π8\frac { \pi } { 8 } , \frac { 7 \pi } { 8 } , \frac { 9 \pi } { 8 } , \frac { 15 \pi } { 8 }
B) 0,2π3,π,4π30 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }
C) π4,3π4,5π4,7π4\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }
D) no solution

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions