Let θ Be an Angle in Standard Position $\tan \theta = - \frac { 15 } { 8 } , \quad 90 ^ { \circ } < \theta < 180 ^ { \circ } \quad$

Multiple Choice

Let θ be an angle in standard position. Name the quadrant in which the angle θ lies.
- $\tan \theta = - \frac { 15 } { 8 } , \quad 90 ^ { \circ } < \theta < 180 ^ { \circ } \quad$ Find $\cos \theta$

A) $- \frac { 8 } { 17 }$
B) $- 8$
C) $\frac { - 8 \sqrt { 23 } } { 23 }$
D) $\frac { - 15 \sqrt { 23 } } { 23 }$