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Solve the Problem EE , That Can Be Placed Across a Resistor Is Given

Question 96

Multiple Choice

Solve the problem.
-The maximum number of volts, EE , that can be placed across a resistor is given by the formula E=PRE = \sqrt { P R } , where P\mathrm { P } is the number of watts of power that the resistor can absorb and R\mathrm { R } is the resistance of the resistor in ohms. Solve this equation for RR . Use the result to determine the resistance of a resistor if PP is 12\frac { 1 } { 2 } watts and EE is 12 volts.


A) R=E2P;288ohms\mathrm { R } = \frac { \mathrm { E } ^ { 2 } } { \mathrm { P } } ; 288 \mathrm { ohms }
B) R=E2P2;576ohms\mathrm { R } = \frac { \mathrm { E } ^ { 2 } } { \mathrm { P } ^ { 2 } } ; 576 \mathrm { ohms }
C) R=E2P;288R = E ^ { 2 } P ; 288 ohms
D) R=E2P2;576ohms\mathrm { R } = \mathrm { E } ^ { 2 } \mathrm { P } ^ { 2 } ; 576 \mathrm { ohms }

Correct Answer:

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