A Multiple-Comparison Procedure for Comparing Four Treatment Means Produced the Confidence

Short Answer

A multiple-comparison procedure for comparing four treatment means produced the confidence intervals shown below. For each pair of means, indicate which mean is larger or indicate that there is no significant difference. $\begin{array}{l}\left(\mu_{\mathrm{A}}-\mu_{\mathrm{B}}\right):(18,34) \\\left(\mu_{\mathrm{A}}-\mu_{\mathrm{C}}\right):(7,23) \\\left(\mu_{\mathrm{A}}-\mu_{\mathrm{D}}\right):(6,18) \\\left(\mu_{\mathrm{B}}-\mu_{\mathrm{C}}\right):(-18,-4) \\\left(\mu_{\mathrm{B}}-\mu_{\mathrm{D}}\right):(-24,-4) \\\left(\mu_{\mathrm{C}}-\mu_{\mathrm{D}}\right):(-10,4)\end{array}$

A) $\mu_{\mathrm{A}}>\mu_{\mathrm{B}} ; \mu_{\mathrm{A}}>\mu_{\mathrm{C}} ; \mu_{\mathrm{A}}>\mu_{\mathrm{D}} ; \mu_{\mathrm{B}}<\mu_{\mathrm{C}} ; \mu_{\mathrm{B}}<\mu_{\mathrm{D}} ;$ no significant difference between $\mu_{\mathrm{C}}$ and $\mu_{\mathrm{D}}$
B) $\mu_{\mathrm{A}}>\mu_{\mathrm{B}} ; \mu_{\mathrm{A}}>\mu_{\mathrm{C}} ; \mu_{\mathrm{A}}>\mu_{\mathrm{D}} ; \mu_{\mathrm{B}}<\mu_{\mathrm{C}}: \mu_{\mathrm{B}}<\mu_{\mathrm{D}} ; \mu_{\mathrm{C}}<\mu_{\mathrm{D}}$
C) $\mu_{\mathrm{A}}<\mu_{\mathrm{B}} ; \mu_{\mathrm{A}}<\mu_{\mathrm{C}} ; \mu_{\mathrm{A}}<\mu_{\mathrm{D}} ; \mu_{\mathrm{B}}>\mu_{\mathrm{C}} ; \mu_{\mathrm{B}}>\mu_{\mathrm{D}}$ ; no significant difference between $\mu_{\mathrm{C}}$ and $\mu_{\mathrm{D}}$
D) no significant difference between $\mu_{\mathrm{A}}$ and $\mu_{\mathrm{B}} ; \mu_{\mathrm{A}}<\mu_{\mathrm{C}} ; \mu_{\mathrm{A}}<\mu_{\mathrm{D}} ; \mu_{\mathrm{B}}>\mu_{\mathrm{C}}$ ; $\mu_{\mathrm{B}}>\mu_{\mathrm{D}}$ ; no significant difference between $\mu_{\mathrm{C}}$ and $\mu \mathrm{D}$