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Use Mathematical Induction to Prove That the Statement Is True 5+2⋅5+3⋅5+…+5n=5n(n+1)25 + 2 \cdot 5 + 3 \cdot 5 + \ldots + 5 n = \frac { 5 n ( n + 1 ) } { 2 }

Question 224

Essay

Use mathematical induction to prove that the statement is true for every positive integer n.
- 5+2⋅5+3⋅5+…+5n=5n(n+1)25 + 2 \cdot 5 + 3 \cdot 5 + \ldots + 5 n = \frac { 5 n ( n + 1 ) } { 2 }

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