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A Lake Is Stocked with 545 Fish of a New P(t)=34061+5.07e0.25tP ( t ) = \frac { 3406 } { 1 + 5.07 e ^ { - 0.25 t } }

Question 198

Multiple Choice

A lake is stocked with 545 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 3406. The population of fish in the lake after time t, in
Months, is given by the function P(t) P(t) =34061+5.07e0.25tP ( t ) = \frac { 3406 } { 1 + 5.07 e ^ { - 0.25 t } } . After how many months will the population be 2405?


A) 7 mo
B) 12 mo
C) 17 mo
D) 10 mo

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