If an Object Is Thrown Upward with an Initial Velocity $96 \mathrm { ft } / \mathrm { sec }$

Multiple Choice

If an object is thrown upward with an initial velocity of $96 \mathrm { ft } / \mathrm { sec }$ , its height after $\mathrm { t }$ sec is given by $s ( t ) = 96 \mathrm { t } - 16 \mathrm { t } ^ { 2 }$ . Find the maximum height attained by the object. (The object will attain maximum height exactly at the halfway point in terms of the time $t$ , where $t = 0$ is at the beginning of the object's flight, and the final time is when the object hits the ground.)

A) 96 ft
B) 128 ft
C) 80 ft
D) 144 ft