Give a Rule for the Piecewise-Defined Function $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \\ x + 1 & \text { if } x > 1 \end{array} ; \right.$

Multiple Choice

Give a rule for the piecewise-defined function. Then give the domain and range.
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A) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \\ x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( \infty , \infty )$ , Range: $( \infty , \infty )$
B) $f ( x ) = \left\{ \begin{array} { l l } 2 x & \text { if } x \leq 1 \\ x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( \infty , \infty )$ , Range: $( \infty , \infty )$
C) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \\ x + 2 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( \infty , 2 ) \cup ( 2 , \infty )$ , Range: $( \infty , \infty )$
D) $f ( x ) = \left\{ \begin{array} { l l } - x & \text { if } x \leq 1 \\ 2 x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( \infty , \infty )$ , Range: $( \infty , 2 ) \cup ( 2 , \infty )$