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Decide What Values of the Variable Cannot Possibly Be Solutions 13x+8x=10\frac { 1 } { 3 x } + \frac { 8 } { x } = 10

Question 46

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 13x+8x=10\frac { 1 } { 3 x } + \frac { 8 } { x } = 10


A) 0
B) 3- 3
C) 1,3
D) 0,130 , - \frac { 1 } { 3 }

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