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Decide What Values of the Variable Cannot Possibly Be Solutions 1x31x+8=10\frac { 1 } { x - 3 } - \frac { 1 } { x + 8 } = 10

Question 183

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 1x31x+8=10\frac { 1 } { x - 3 } - \frac { 1 } { x + 8 } = 10


A) 18,13- \frac { 1 } { 8 } , \frac { 1 } { 3 }
B) 3,8- 3,8
C) 8,3- 8,3
D) 13,18- \frac { 1 } { 3 } , \frac { 1 } { 8 }

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