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Decide What Values of the Variable Cannot Possibly Be Solutions xx31x+9=10x2+6x27\frac { x } { x - 3 } - \frac { 1 } { x + 9 } = \frac { 10 } { x ^ { 2 } + 6 x - 27 }

Question 383

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- xx31x+9=10x2+6x27\frac { x } { x - 3 } - \frac { 1 } { x + 9 } = \frac { 10 } { x ^ { 2 } + 6 x - 27 }


A) 9,3- 9,3
B) 9,0,3- 9,0,3
C) 3,9,27- 3,9 , - 27
D) 3,0,9- 3,0,9

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