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Decide What Values of the Variable Cannot Possibly Be Solutions 3x+5+8x+2=10x2+7x+10\frac { 3 } { x + 5 } + \frac { 8 } { x + 2 } = \frac { 10 } { x ^ { 2 } + 7 x + 10 }

Question 80

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 3x+5+8x+2=10x2+7x+10\frac { 3 } { x + 5 } + \frac { 8 } { x + 2 } = \frac { 10 } { x ^ { 2 } + 7 x + 10 }


A) \varnothing
B) {397}\left\{ - \frac { 39 } { 7 } \right\}
C) {3611}\left\{ - \frac { 36 } { 11 } \right\}
D) {5611}\left\{ - \frac { 56 } { 11 } \right\}

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