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Decide What Values of the Variable Cannot Possibly Be Solutions 5x243x2+5x+6=3x2+x6\frac { 5 } { x ^ { 2 } - 4 } - \frac { 3 } { x ^ { 2 } + 5 x + 6 } = \frac { 3 } { x ^ { 2 } + x - 6 }

Question 414

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 5x243x2+5x+6=3x2+x6\frac { 5 } { x ^ { 2 } - 4 } - \frac { 3 } { x ^ { 2 } + 5 x + 6 } = \frac { 3 } { x ^ { 2 } + x - 6 }


A) {3,2,2}\{ - 3 , - 2,2 \}
B) {275}\left\{ \frac { 27 } { 5 } \right\}
C) {15}\{ 15 \}
D) {7}\{ 7 \}

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