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Decide What Values of the Variable Cannot Possibly Be Solutions 10x2=1+12x+2\frac { 10 } { x - 2 } = 1 + \frac { 12 } { x + 2 }

Question 224

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 10x2=1+12x+2\frac { 10 } { x - 2 } = 1 + \frac { 12 } { x + 2 }


A) {6,8}\{ - 6,8 \}
B) {12,8}\{ - 12,8 \}
C) {6,8}\{ 6 , - 8 \}
D) \varnothing

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