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Provide a STATEMENT/REASON Proof for the Congruence AC=BD,ACD=BDC\mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }

Question 66

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Provide a STATEMENT/REASON proof for the congruence.
- Provide a STATEMENT/REASON proof for the congruence. -  Given:  \mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }  Prove:  \triangle \mathrm { ACD } \simeq \triangle \mathrm { BDC }
Given: AC=BD,ACD=BDC\mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }
Prove: ACDBDC\triangle \mathrm { ACD } \simeq \triangle \mathrm { BDC }

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\[\begin{array}{l}
\text { STATEMENTS|RE...

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