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Make a Probability Distribution for the Given Set of Events  Sum  Probability 41/551/561/571/581/5\begin{array}{l|c}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 5 \\5 & 1 / 5 \\6 & 1 / 5 \\7 & 1 / 5 \\8 & 1 / 5\end{array}

Question 47

Multiple Choice

Make a probability distribution for the given set of events.
-Suppose that you start with a normal deck of 52 cards and remove everything except the twos, threes, and fours. So you now have a deck of twelve cards consisting of four twos, four threes, and
Four fours. A card is drawn at random and replaced then another card is drawn at random and
Replaced. Make a probability distribution for the sum of the two numbers that are drawn.


A)
 Sum  Probability 41/551/561/571/581/5\begin{array}{l|c}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 5 \\5 & 1 / 5 \\6 & 1 / 5 \\7 & 1 / 5 \\8 & 1 / 5\end{array}
B)
 Sum  Probability 41/952/963/972/981/9\begin{array}{l|l}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 9 \\5 & 2 / 9 \\6 & 3 / 9 \\7 & 2 / 9 \\8 & 1 / 9\end{array}

C)
 Sum  Probability 41/951/961/971/981/991/9101/9111/9121/9\begin{array}{l|l}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 9 \\5 & 1 / 9 \\6 & 1 / 9 \\7 & 1 / 9 \\8 & 1 / 9 \\9 & 1 / 9 \\10 & 1 / 9 \\11 & 1 / 9 \\12 & 1 / 9\end{array}

D)
 Sum  Probability 41/361/381/3\begin{array}{l|l}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 3 \\6 & 1 / 3 \\8 & 1 / 3\end{array}

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