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Convert the Polar Equation to a Rectangular Equation r=4secθsecθ+2r = \frac { 4 \sec \theta } { \sec \theta + 2 }

Question 83

Multiple Choice

Convert the polar equation to a rectangular equation.
- r=4secθsecθ+2r = \frac { 4 \sec \theta } { \sec \theta + 2 }


A) 3x2y216x+16=03 x ^ { 2 } - y ^ { 2 } - 16 x + 16 = 0
B) 3y2x2+16=03 y ^ { 2 } - x ^ { 2 } + 16 = 0
C) 3x2y2+16=03 x ^ { 2 } - y ^ { 2 } + 16 = 0
D) 3y2x216y+16=03 y ^ { 2 } - x ^ { 2 } - 16 y + 16 = 0

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