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Transform the Polar Equation to an Equation in Rectangular Coordinates $\theta = \frac { \pi } { 3 }$

Question 264

Multiple Choice

Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation.
- $\theta = \frac { \pi } { 3 }$
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta = \frac { \pi } { 3 } A) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis B) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole D) \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} ; circle, radius \frac{\pi}{3} center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$
A)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta = \frac { \pi } { 3 } A) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis B) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole D) \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} ; circle, radius \frac{\pi}{3} center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$
$y=\sqrt{3} x$ ; line through the pole making
an angle of $\frac{\pi}{3}$ with the polar axis

B)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta = \frac { \pi } { 3 } A) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis B) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole D) \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} ; circle, radius \frac{\pi}{3} center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$
$y=-\frac{\sqrt{3}}{3} x$ ; line through the pole making
an angle of $\frac{\pi}{3}$ with the polar axis

C)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta = \frac { \pi } { 3 } A) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis B) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole D) \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} ; circle, radius \frac{\pi}{3} center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$
$y=-\frac{\pi}{3}$ ; horizontal line $\frac{\pi}{3}$ units
below the pole

D)
$Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - \theta = \frac { \pi } { 3 } A) y=\sqrt{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis B) y=-\frac{\sqrt{3}}{3} x ; line through the pole making an angle of \frac{\pi}{3} with the polar axis C) y=-\frac{\pi}{3} ; horizontal line \frac{\pi}{3} units below the pole D) \left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} ; circle, radius \frac{\pi}{3} center at \left(\frac{\pi}{3}, 0\right) in rectangular coordinates$
$\left(x-\frac{\pi}{3}\right) ^{2}+y^{2}=\frac{\pi^{2}}{9} ;$ circle, radius $\frac{\pi}{3}$
center at $\left(\frac{\pi}{3}, 0\right)$ in rectangular coordinates

Transform the Polar Equation to an Equation in Rectangular Coordinates θ=π3\theta = \frac { \pi } { 3 }θ=3π​

Multiple Choice

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Transform the Polar Equation to an Equation in Rectangular Coordinates $\theta = \frac { \pi } { 3 }$

Correct Answer:
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