Solve the Equation on the Interval $$0 \leq \theta < 2 \pi$$

Multiple Choice

Solve the equation on the interval $$0 \leq \theta < 2 \pi$$
- $$2 \sqrt { 3 } \sin ( 4 \theta ) = 3$$

A) 0
B) $\frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } , \frac { 19 \pi } { 12 }$
C) $0 , \frac { \pi } { 4 } , \pi$
D) $\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }$