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Solve the Equation on the Interval 0θ<2π0 \leq \theta < 2 \pi

Question 192

Multiple Choice

Solve the equation on the interval 0θ<2π0 \leq \theta < 2 \pi
- 2cos(2θ) =1\sqrt { 2 } \cos ( 2 \theta ) = 1


A) π4,3π4,5π4,7π4\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }
B) 0,2π3,π,4π30 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }
C) π8,7π8,9π8,15π8\frac { \pi } { 8 } , \frac { 7 \pi } { 8 } , \frac { 9 \pi } { 8 } , \frac { 15 \pi } { 8 }
D) No solution

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