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Solve the Equation on the Interval 0θ<2π0 \leq \theta < 2 \pi

Question 383

Multiple Choice

Solve the equation on the interval 0θ<2π0 \leq \theta < 2 \pi
- 2cos(2θ) =32 \cos ( 2 \theta ) = \sqrt { 3 }


A) π2\frac { \pi } { 2 }
B) 3π2\frac { 3 \pi } { 2 }
C) π6,11π6\frac { \pi } { 6 } , \frac { 11 \pi } { 6 }
D) π12,11π12,13π12,23π12\frac { \pi } { 12 } , \frac { 11 \pi } { 12 } , \frac { 13 \pi } { 12 } , \frac { 23 \pi } { 12 }

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