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Solve the Equation on the Interval 0θ<2π0 \leq \theta < 2 \pi

Question 43

Multiple Choice

Solve the equation on the interval 0θ<2π0 \leq \theta < 2 \pi
- sin2(2θ) =1\sin ^ { 2 } ( 2 \theta ) = 1


A) 0,2π3,π,4π30 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }

B) π8,9π8\frac { \pi } { 8 } , \frac { 9 \pi } { 8 }

C) π4,3π4,5π4,7π4\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }

D) No solution

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