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Solve the Problem θ\theta (In Degrees) to the Horizontal with an Initial Speed V0

Question 309

Essay

Solve the problem.
-The path of a projectile fired at an inclination θ\theta (in degrees) to the horizontal with an initial speed v0 is a
parabola. The range R of the projectile, that is, the horizontal distance that the projectile travels, is found by using the
formula R=v02 gsin(2θ)R = \frac { \mathrm { v } _ { 0 } ^ { 2 } } { \mathrm {~g} } \sin ( 2 \theta ) where g is the acceleration due to gravity. The maximum height H of the projectile is H=v024 g(1cos(2θ))\mathrm { H } = \frac { \mathrm { v } _ { 0 } ^ { 2 } } { 4 \mathrm {~g} } ( 1 - \cos ( 2 \theta ) ) Find the range R and the maximum height H in terms of g if the projectile is fired with an initial speed of 200 meters per
second at an angle of 15° and then at an angle of 22.5°. Do not use a calculator, but simplify the answers.

Correct Answer:

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\[\begin{array} { l }
\theta = 15 ^ { \...

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