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Solve the Problem P=50et/300\mathrm { P } = 50 \mathrm { e } ^ { - \mathrm { t } / 300 }

Question 9

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Solve the problem.
-Instruments on a satellite measure the amount of power generated by the satellite's power supply. The time t
and the power P can be modeled by the function P P=50et/300\mathrm { P } = 50 \mathrm { e } ^ { - \mathrm { t } / 300 } , where t is in days and P is in watts. How much
power will be available after 378 days? Round to the nearest hundredth.

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