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Solve the Problem D(h)=4e0.35 h\mathrm { D } ( \mathrm { h } ) = 4 \mathrm { e } ^ { - 0.35 \mathrm {~h} }

Question 28

Short Answer

Solve the problem.
-A cancer patient undergoing chemotherapy is injected with a particular drug. The function D(h)=4e0.35 h\mathrm { D } ( \mathrm { h } ) = 4 \mathrm { e } ^ { - 0.35 \mathrm {~h} } gives the number of milligrams D of this drug that is in the patient's bloodstream h hours after the drug has
been administered. How many milligrams of the drug were injected? To the nearest milligram, how much of the
drug will be present after 2 hours?

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