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Solve the Problem N(t)=30001+21.2e0.54t\mathrm { N } ( \mathrm { t } ) = \frac { 3000 } { 1 + 21.2 \mathrm { e } ^ { - 0.54 t } }

Question 126

Multiple Choice

Solve the problem.
-In a town whose population is 3000, a disease creates an epidemic. The number of people, N, infected t days after the disease has begun is given by the function N(t) =30001+21.2e0.54t\mathrm { N } ( \mathrm { t } ) = \frac { 3000 } { 1 + 21.2 \mathrm { e } ^ { - 0.54 t } } Find the number of infected people after 10 days.


A) 142 people
B) 2000 people.
C) 1000 people
D) 2737 people

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