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Solve the Problem s=160t16t2\mathrm { s } = 160 \mathrm { t } - 16 \mathrm { t } ^ { 2 }

Question 152

Multiple Choice

Solve the problem.
-A ball is thrown vertically upward with an initial velocity of 160 feet per second. The distance in feet of the ball from the ground after t seconds is s=160t16t2\mathrm { s } = 160 \mathrm { t } - 16 \mathrm { t } ^ { 2 } . For what interval of time is the ball more than 256 above the
Ground? A) {x1.5sec<x<8.5sec}\{ x \mid 1.5 \mathrm { sec } < x < 8.5 \mathrm { sec } \}
B) {x2sec<x<8sec}\{ x \mid 2 \sec < x < 8 \mathrm { sec } \}
C) {x4.5sec<x<5.5sec}\{ x \mid 4.5 \mathrm { sec } < x < 5.5 \mathrm { sec } \}
D) {x7sec<x<13sec}\{ x \mid 7 \sec < x < 13 \mathrm { sec } \}

Correct Answer:

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