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Solve the Problem s=128t16t2\mathrm { s } = 128 \mathrm { t } - 16 \mathrm { t } ^ { 2 }

Question 300

Multiple Choice

Solve the problem.
-A ball is thrown vertically upward with an initial velocity of 128 feet per second. The distance in feet of the ball from the ground after t seconds is s=128t16t2\mathrm { s } = 128 \mathrm { t } - 16 \mathrm { t } ^ { 2 } . For what intervals of time is the ball less than 112 above the
Ground (after it is tossed until it returns to the ground) ? A) {x0sec<x<3.5sec\{ x \mid 0 \mathrm { sec } < x < 3.5 \mathrm { sec } and 4.5sec>x>8sec}4.5 \mathrm { sec } > x > 8 \mathrm { sec } \}
B) {x0sec<x<0.5sec\{ \mathrm { x } \mid 0 \mathrm { sec } < \mathrm { x } < 0.5 \mathrm { sec } and 7.5sec>x>8sec}7.5 \mathrm { sec } > x > 8 \mathrm { sec } \}
C) {x0sec<x<1sec\{ x \mid 0 \sec < x < 1 \mathrm { sec } and 7sec>x>8sec}7 \sec > x > 8 \mathrm { sec } \}
D) {x1sec<x<7sec}\{ \mathrm { x } \mid 1 \mathrm { sec } < \mathrm { x } < 7 \mathrm { sec } \}

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