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Solve the Problem x=6p+120,0p20x = - 6 p + 120 , \quad 0 \leq p \leq 20

Question 196

Multiple Choice

Solve the problem.
-The price p (in dollars) and the quantity x sold of a certain product obey the demand equation x=6p+120,0p20x = - 6 p + 120 , \quad 0 \leq p \leq 20 What quantity x maximizes revenue? What is the maximum revenue?


A) 60; $600
B) 90; $450
C) 30; $450
D) 120; $600

Correct Answer:

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